设f(x)=sinx·cos2x·sin3x·cos4x,则f(π/6)=_____.
问题描述:
设f(x)=sinx·cos2x·sin3x·cos4x,则f(π/6)=_____.
答
f(x)=sinx·cos2x·sin3x·cos4x,
f(π/6)=sinπ/6*cosπ/3*sinπ/2*cos2π/3
=1/2*1/2*1*(-1/2)
=-1/8