(x-1)(2x-1)-36=0怎么算,
问题描述：
(x-1)(2x-1)-36=0怎么算,
答
(x - 1)(2x - 1) - 36 = 0
2x² - 3x - 35 = 0
(2x + 7)(x - 5) = 0
x = 5 或 x = -7/22x² - 3x - 35 = 0怎样变(2x + 7)(x - 5) = 0的？？十字相乘