若函数f(x)满足f(1/x +1)=lg2 √x,则f(3)=多少
问题描述:
若函数f(x)满足f(1/x +1)=lg2 √x,则f(3)=多少
答
let 1/x + 1 = y
x = 1/(y-1)
f(y) = lg2sqrt(x) = -1/2 lg2 (y-1)
f(3) = -1/2 lg2 (3-1) = -1/2