求定积分 (lnx)^2/1+x
问题描述:
求定积分 (lnx)^2/1+x
答
是(lnx)^(1/2)+x Warning:Explicit integral could not be found.
(lnx)^2/1+x log(x)^2*x-2*x*log(x)+2*x+1/2*x^2
log(x)即表示lnx