sinθ-cosθ=1/2,则tanθ+cotθ=

问题描述:

sinθ-cosθ=1/2,则tanθ+cotθ=

解sinθ-cosθ=1/2两边平方得:(sinθ-cosθ)²=1/4即1-2sinθcosθ=1/4∴2sinθcosθ=3/4∴sinθcosθ=3/8tanθ+cotθ=(sinθ/cosθ)+(cosθ/sinθ)=(sin²θ+cos²θ)/(sinθcosθ)=1/(3/8)=8/3...