N+(N+1)(N+2)(N+3)+1是哪个数的平方 快
问题描述:
N+(N+1)(N+2)(N+3)+1是哪个数的平方 快
答
回答:N*(N+1)*(N+2)*(N+3)+1
=N*(N+3)*(N+1)*(N+2)+1
=(N^2+3N)*(N^2+3N+2)+1
=(N^2+3N)^2+2(N2+3N)+1
=(N^2+3N+1)^2
为N^2+3N+1的平方