怎么计1/2+1/4+1/8+1/16+...+1/(2的n次幂)
问题描述:
怎么计1/2+1/4+1/8+1/16+...+1/(2的n次幂)
答
1/2+1/4+1/8+1/16+...+1/2^n
=1/2*(1-(1/2)^n)*/(1-1/2)
=1-1/2^n