赶快帮忙计算∫(π/6,π/2)(cos^2x)dx和∫(-2,-1)dx/(11+5x)^3

问题描述:

赶快帮忙计算∫(π/6,π/2)(cos^2x)dx和∫(-2,-1)dx/(11+5x)^3
同上

∫(π/6,π/2)(cos^2x)dx=(1/2)[∫(π/6,π/2)(2cos^2x - 1)dx ]+(1/2)∫(π/6,π/2)dx=(1/2)[∫(π/6,π/2)(cos2x)dx ]+(1/2)(π/2-π/6)=(1/4)[∫(π/6,π/2)(cos2x)d2x ]+(1/2)*(π/3)=(1/4)*sin2x |(π/6...