(3a-b+2c)(3a+b-2c)+(b+2c)平方

问题描述:

(3a-b+2c)(3a+b-2c)+(b+2c)平方

(3a-b 2c)(3a b-2c) (b 2c)²
=9a²–(b–2c)² (b 2c)²
=9a² 8bc

(3a-b+2c)(3a+b-2c)+(b+2c)^2
=(3a-(b-2c))(3a+b-2c)+(b+2c)^2
=(3a)^2-(b-2c)^2+(b+2c)^2
=9a^2-8bc