sin25π/6+cos25π/3+tan25π/4等于多少?

问题描述:

sin25π/6+cos25π/3+tan25π/4等于多少?

sin(25π/6)+cos(25π/3)+tan(25π/4)
=sin(25π/6-4π)+cos(25π/3-8π)+tan(25π/4-6π)
=sin(π/6)+cos(π/3)+tan(π/4)
=(1/2)+(1/2)+(+1)
=2