已知(x+y)(x+y-10)+25=0,且x-y=3,求x,y的值.
问题描述:
已知(x+y)(x+y-10)+25=0,且x-y=3,求x,y的值.
答
设x+y=a,则a(a-10)+25=0,
即a2-10a+25=0,(a-5)2=0,
∴a-5=0,
则a=5,即x+y=5,
根据题意得:
,
x+y=5 x−y=3
解得:
.
x=4 y=1