(4/x-5)+(x-3)/(12-x)=(x-45)/(x^2-17x+60)
问题描述：
(4/x-5)+(x-3)/(12-x)=(x-45)/(x^2-17x+60)
答
(4/x-5)+(x-3)/(12-x)=(x-45)/(x^2-17x+60)(4/x-5)+(x-3)/(12-x)=(x-45)/(x-5)(x-12)通分,两边同乘以(x-5)(x-12)得4(x-12)-(x-3)(x-5)=x-45-x^2+11x-18=0x^2-11x+18=0(x-2)(x-9)=0x=2或x=9经检验,都是方程的根!...