5(x²-x)=3(x²+x) (x-2)²=(2x+3)²=0 (x-2)(x-3)=12 (x-1)(x-2)=12
问题描述:
5(x²-x)=3(x²+x) (x-2)²=(2x+3)²=0 (x-2)(x-3)=12 (x-1)(x-2)=12
答
5(x²-x)=3(x²+x) 5x(x-1)-3x(x+1)=0x(5x-5-3x-3)=0x(2x-8)=0x=0,x=4(x-2)²=(2x+3)²(2x+3)²-(x-2)²=0(2x+3+x-2)(2x+3-x+2)=0(3x+1)(x+5)=0x=-1/3,x=-5(x-2)(x-3)=12 x&sup...