若2a²+4ab+4b²-2a+1=0,求b的a次方

问题描述:

若2a²+4ab+4b²-2a+1=0,求b的a次方

2a²+4ab+4b²-2a+1=0a²+4ab+4b²+a²-2a+1=0(a+2b)²+(a-1)²=0(a+2b)²=0,(a-1)²=0a+2b=0,a=11+2b=0b=-1/2b^a=(-1/2)^1=-1/2