化简:cos(π/2+α)-tan(π/2-α)sin(π/2+α)
问题描述:
化简:cos(π/2+α)-tan(π/2-α)sin(π/2+α)
答
cos(π/2+α)-tan(π/2-α)sin(π/2+α)
=-sinα-cotαcosα
=-sinα-(cosα/sinα)cosα
=-(sin²α+cos²α)/sinα
=-1/sinα
=-cscα