已知a.b.c满足1/2【a-b】+根号2b+c+c²-c+1/4=0.求a(b+c)的值
问题描述:
已知a.b.c满足1/2【a-b】+根号2b+c+c²-c+1/4=0.求a(b+c)的值
答
根据题意得
a-b=0
2b+c=0
c²-c+1/4=(c-1/2)²=0
解得
c=1/2
b=-1/4
a=-1/4
于是
a(b+c)
=-1/4x(-1/4+1/2)
=-1/4x1/4
=-1/16