（-27/8）^(2/3)+(0.01)^-(1/2)-(根号2-1）^(-1)+(根号3-根号2）^0=
问题描述：
（-27/8）^(2/3)+(0.01)^-(1/2)-(根号2-1）^(-1)+(根号3-根号2）^0=
题目有点烦,都是分数次方.我算出的答案不太对劲.哪位兄弟教教我
答
=[(-3/2)^3]^(2/3)+1/√0.01-1/(√2-1)+1
=(-3/2)^2+1/0.1-(√2+1)/(√2+1)(√2-1)+1
=9/4+10+(√2+1)/(2-1)+1
=53/4+√2+1
=57/4+√2