(10-x)^2+(4/3 x-40/3)^2=49
问题描述：
(10-x)^2+(4/3 x-40/3)^2=49
x=?
答
(10-x)^2+(4/3 x-40/3)^2=49 解,得：(10-x)^2+(4x-40)^2/9=499(10-x)^2+(4x-40)^2=4419(100-20x+x^2)+(16x-320x+1600)-441==0900-180x+9x^2+16x-320x+1600-441==02059-484x+9x^2==0（以后的不好解了@,@）...