根号27+(2-根号6)/根号3-(兀-3)^0
问题描述:
根号27+(2-根号6)/根号3-(兀-3)^0
答
根号27+(2-根号6)/根号3-(兀-3)^0
=3√3+(2-√6)√3/3 - 1
=3√3+ 2√3/3-√2 - 1
=11√3/3 -√2 - 1