如何对函数f(x)=(x+1)ln x-x+1 求导?
问题描述:
如何对函数f(x)=(x+1)ln x-x+1 求导?
答
f(x)=(x+1)ln x-x+1 f'(x)=(x+1)'ln x+(x+1)(ln x)'-x'+1' =ln x+(x+1)(1/x)-1 =ln x+1+1/x-1 =ln x+1/x
如何对函数f(x)=(x+1)ln x-x+1 求导?
f(x)=(x+1)ln x-x+1 f'(x)=(x+1)'ln x+(x+1)(ln x)'-x'+1' =ln x+(x+1)(1/x)-1 =ln x+1+1/x-1 =ln x+1/x