(1+2y)xdx+(1+x^2)dy=0的微分方程的通解.答案是(1+x^2)(1+Y^2)=c.
问题描述:
(1+2y)xdx+(1+x^2)dy=0的微分方程的通解.答案是(1+x^2)(1+Y^2)=c.
答
(1+2y)xdx+(1+x^2)dy=0 分离变量: x/(1+x^2) dx +1/(1+2y) dy=0 积分: ∫x/(1+x^2)dx+∫1/(1+2y)dy=0 1/2∫2x/(1+x^2)dx+1/2∫1/(1+2y)d2y=0 1/2∫1/(1+x^2)dx^2+1/2∫1/(1+2y)d2y=0 ...厉害谢谢啊