cosπ/12+(根号3)×sinπ/12的值
问题描述：
cosπ/12+(根号3)×sinπ/12的值
答
原式=2(cosπ/12*1/2+sinπ/12*√3/2)
=2(cosπ/12cosπ/3+sinπ/12sinπ/3)
=2cos(π/3-π/12)
=2sinπ/4
=2×√2/2
=√2