已知x-3y=0,求(2x+y)/(x^2-2xy+y^2)X(x-y)

问题描述:

已知x-3y=0,求(2x+y)/(x^2-2xy+y^2)X(x-y)

直接把x=3y代入就可以了『也可以先化简为:(2x+y)/(x-y)』结果为7/2

(2x+y)/(x^2-2xy+y^2)X(x-y)=(2x+y)/(x-y)² *(x-y)=(2x+y)/(x-y)
x-3y=0,x=3y
(2x+y)/(x-y)=(6y+y)/(3y-y)=7/2