4b²c²-(b²+c²)² (因式分解,
问题描述:
4b²c²-(b²+c²)² (因式分解,
答
4b²c²-(b²+c²)²
=(2bc+b²+c²)(2bc-b²-c²)
=-(b²+2bc+c²)(b²-2bc+c²)
=-(b+c)²(b-c)²