若f(sin2x)=cos2x,则f(1/2)=

问题描述:

若f(sin2x)=cos2x,则f(1/2)=

sin2x=1/2 2x取π/6 f(1/2)=cosπ/6=√3/2

f(sin2x)=cos2x,
设sin2x=1/2,则有cos2x=土根号3/2
则f(1/2)=土根号3/2