计算：（x+1/x²-x-x/x²-2x+1）÷1/x;a²-b²/ab÷(1/a-1/b).
问题描述：
计算：（x+1/x²-x-x/x²-2x+1）÷1/x;a²-b²/ab÷(1/a-1/b).
答
（x+1/x²-x-x/x²-2x+1）÷1/x
=[(x+1)/x(x-1)-x/(x-1)²】÷1/x
=(x+1)/(x-1)-x²/(x-1)²
=【(x+1)(x-1)-x²】/(x-1)²
=1/(x-1)²
a²-b²/ab÷(1/a-1/b).
=（a+b）（a-b）/ab÷（b-a）/ab
=-a-b
如果本题有什么不明白可以追问,