我又来了哈..分解公因式x(x+y)(x-y)-x(x+y)^2

分类: 作业答案 • 2022-02-26 08:59:49

问题描述：

我又来了哈..分解公因式
x(x+y)(x-y)-x(x+y)^2

答

这么简单也问人？
x(x+y)(x-y)-x(x+y)^2
=(x+y)(x(x-y)-x(x+y))
=(x-y)(x^2-xy-x^2-xy)
=-2xy(x-y)

答

x(x+y)(x-y-x-y)=-2yx(x+y)

答

原式＝(x+y)(x^2-xy)-(x+y)(x^2+xy)
=(x+y)[x^2-xy-x^2-xy]
=(x+y)(-2xy)

答

x(x+y)(x-y-x-y)=-2xy(x+y)