x的四次方+2x²y²+y的四次方-4x²y²【因式分解】
问题描述：
x的四次方+2x²y²+y的四次方-4x²y²【因式分解】
答
答：
x的四次方+2x²y²+y的四次方-4x²y²
=x^4+2x²y²+y^4-4x²y²
=x^4-2x²y²+y^4
=(x²-y²)²
=(x-y)²(x+y)²
答
x的四次方+2x²y²+y的四次方-4x²y²
=x的四次方-2x²y²+y的四次方
=(x²-y²)²
=(x+y)²(x-y)²
答
解
x^4++2x²y²+y^4-4x²y²
=(x²+y²)²-(2xy)²
=[(x²+y²)-2xy][(x²+y²)+2xy]
=(x-y)²(x+y)²
答
原式=x⁴-2x²y²+y⁴
=(x²-y²)²
=(x+y)²(x-y)²