2倍的log以3为底2的对数－log以3为底9分之32的对数+log以3为底8的对数－5的log以5为底3的对数的次方

分类: 作业答案 • 2021-12-19 10:57:54

问题描述：

答

2log(3)2-log(3)32/9+log(3)8-5^log(5)3
=log(3)[4/(32/9)*8]-3
=log(3)9-3
=2-3
=-1

答

2log[3](2)-log[3](32/9)+log[3](8)-5^(log[5](3))
=log[3](2^2/32*9*8)-3
=log[3](9)-3
=2-3
=-1
注:方括号内为对数之底

答

2log(3)2-log(3)32/9+log(3)8-5^log(5)3
=2log(3)2-log(3)2^5+log(3)9+log(3)2^3-3
=2log(3)2-5log(3)2+log(3)3^2+3log(3)2-3
=2-3
=-1

答

题目请补充完整几次访?