问(x-1/x-2)-(x-2/x-3)-(x-3/x-4)+(x-4/x-5)的值拜托各位大神要过程的

问题描述:

问(x-1/x-2)-(x-2/x-3)-(x-3/x-4)+(x-4/x-5)的值拜托各位大神
要过程的

原式=(x-2+1)/(X-2) - (X-3+1)/(X-3) - (X-4+1)/(X-4)+(X-5+1)/(X-5) =1+ 1/(X-2) -1 - 1/(X-3) -1 - 1/(X-4) +1 + 1/(X-5) =1/(X-2) + 1/(X-5) - 1/(X-3) - 1/(X-4) =(X-5+X-2)/(X-2)(X-5) - (X-4+X-3)/(X-3)(X-4) ...