1:49.9²+9.98+0.1² 2:99²+1991:(a+b)²+2(a+b)c+c² 2:4a(a-b)+b²3:4xy²-4x²y-y³ 4:(4a²+1)²-16a²

问题描述:

1:49.9²+9.98+0.1² 2:99²+199
1:(a+b)²+2(a+b)c+c² 2:4a(a-b)+b²
3:4xy²-4x²y-y³ 4:(4a²+1)²-16a²

1.49.9²+9.98+0.1²=(49.9+0.1)²=2500
2.99²+199=99²+198+1=(99+1)²=10000
3.(a+b)²+2(a+b)c+c² =(a+b+c)²
4.4a(a-b)+b²=4a²-4ab+b²=(2a-b)²
5.4xy²-4x²y-y³ =-y(4x²-4xy+y²)=-y(2x-y)²
6.(4a²+1)²-16a² =(4a²-4a+1)(4a²+4a+1)=(2a-1)²(2a+1)²

1. 49.9²+9.98+0.1²
=49.9²+2*49.9*0.1+0.1²
=(49.9+0.1)²
=2500
2. 99²+199
=(100-1)²+(200-1)
= (10000-200+1)+(200-1)
=10000-200+1+200-1
=10000
3.( a+b)²+2(a+b)c+c²
=[( a+b)+c]²
=(a+b+c)²
4. 4a(a-b)+b²
=4a²-4ab+b²
=(2a)²-2*(2a)*b+b²
=(2a+b)²
5. 4xy²-4x²y-y³
=y(4xy-4x²-y²)
=-y(4x²-4xy+y²)
=-y(2x-y)²
6.(4a²+1)²-16a²
=(4a²+1)²-(4a)²
=(4a²+1+4a)(4a²+1-4a)
=(2a+1)²(2a-1)²
=(4a²-1)²

49.9²+9.98+0.1²
=49.9²+2×49.9×0.1+0.1
=(49.9+0.1)²
=50²
=2500
99²+199
=(100-1)²+199
=10000-2×100×1+1+199
=10000
(a+b)²+2(a+b)c+c²
=(a+b+c)²
4a(a-b)+b²
=4a²-4ab+b²
=(2a)²-2×2a×b+b²
=(2a-b)²
4xy²-4x²y-y³
=-y(-4xy+4x²+y²)
=-y(2x-y)²
(4a²+1)²-16a²
=(4a²+1+4a)(4a²+1-4a)
=(2a+1)²(2a-1)²

1.49.9²+9.98+0.1²=(49.9+0.1)²=2500
2.99²+199=99²+198+1=(99+1)²=10000
3.(a+b)²+2(a+b)c+c² =(a+b+c)²
4.4a(a-b)+b²=4a²-4ab+b²=(2a-b)²
5.4xy²-4x²y-y³ =-y( 4x²-4xy+y²)=-y(2x-y)²
6. (4a²+1)²-16a² =(4a²-4a+1)(4a²+4a+1)=(2a-1)²(2a+1)²

1:49.9²+9.98+0.1²=(49.9+0.1)² =50²=2500
2:99²+199=(100-1)²+199=100²-200+1+199=100²=10000
1:(a+b)²+2(a+b)c+c²=(a+b+c)
2:4a(a-b)+b²=4a²-4ab+b²=(2a-b)²
3:4xy²-4x²y-y³=-y(4x²-4xy+y²)=-y(2x-y)²
4:(4a²+1)²-16a²=(4a²+1+4a)(4a²+1-4a)=(2a+1)²(2a-1)²

1. 原式=49.9²+2*49.9*0.1+0.1²=(49.9+0.1)²=2500
2. 原式=99²+198+1=99²+2*99*1+1² =(99+1)²=10000
1. 原式=(a+b+c)²
2. 原式=4a²-4ab+b²=(2a-b)²
3. 原式=-y(4x²-4xy+y²)=-y(2x-y)²
4. 原式=(4a²+1-4a)(4a²+1+4a)=(2a-1)²(2a+1)²

1.(49.9+0.1)^2=50^2=2500
2.原式=99^2+1+198=(99+1)^2=100^2=10000
3.原式=(a+b+c)^2
4.原式=4a^2-4ab+b^2=(2a-b)^2
5.原式=-y(4x^2+y^2-4xy)=-y(2x-y)^2
6.原式=(4a^2+1+4a)(4a^2+1-4a)=(2a+1)^2(2a-1)^2
注:^2是平方的意思 ,这种题主要是熟练运用(a±b)^2=a^2+b^2±2ab及(a+b)(a-b)=a^2-b^2