绝对值X+Y-4+根号X-Y+10=0,求x y的值.
问题描述:
绝对值X+Y-4+根号X-Y+10=0,求x y的值.
答
绝对值X+Y-4+根号X-Y+10=0
X+Y-4=0 X-Y+10=0
解得X=-3 Y=7