若(x-2)的平方+15y-11=0,求代数式-3(2x-y)-{7x-[6x+2y-(10x-8y)]-x-2(3x-4y)}的值

问题描述:

若(x-2)的平方+15y-11=0,求代数式-3(2x-y)-{7x-[6x+2y-(10x-8y
)]-x-2(3x-4y)}的值

-3(2x-y)-{7x-[6x+2y-(10x-8y )]-x-2(3x-4y)}
=-6x+3y-7x+(6x+2y-10x+8y)+x+6x-8y
=-13x+3y-4x+10y+7x-8y
=-10x+5y
题目是错的吧?题目没有看到x有平方啊