若 |X-2|+3(y+6)平方=0 代数式2y-x+m/4的值比1/2y-x+m多1,求m
问题描述：
若 |X-2|+3(y+6)平方=0 代数式2y-x+m/4的值比1/2y-x+m多1,求m
RT,PS：|X-2|是X-2的绝对值
答
|X-2|+3(y+6)平方=0
则|X-2|=0,3(y+6)平方=0
x=2,y=-6
2y-x+m/4的值比1/2y-x+m多1
(2y-x+m/4)-(1/2y-x+m) =1
3/2y-3/4m=1
3/2*(-6)-3/4m=1
-3/4m = 1+9 = 10
m = -10*4/3 = -40/3