把下列各式分解因式:(1)x(x+y)(x-y)-x(x-y)的平方

问题描述:

把下列各式分解因式:(1)x(x+y)(x-y)-x(x-y)的平方

x(x+y)(x-y)-x(x-y)的平方
=x(x-y)[(x+y)-(x-y)]
=x(x-y)×2y
=2Xy(X-y)