3/4[(x-30)-10]=x+10

问题描述:

3/4[(x-30)-10]=x+10

3/4[(x-30)-10]=x+10
3/4(x-30-10)=x+10
3/4(x-40)=x+10
3(x-40)=4(x+10)
3x-120=4x+40
4x-3x=-120-40
x=-160

3/4[(x-30)-10]=x+10
3[(x-30)-10]=4(x+10)
3(x-30)-30=4x+40
3x-90-30=4x+40
3x-4x = 40+30+90
-x = 160
x = -160