a/1+b/1=2,则-4a+5ab-4b/3a-2ab+3b=?
问题描述：
a/1+b/1=2,则-4a+5ab-4b/3a-2ab+3b=?
答
题目错了吧,因该是1/a+1/b=2则(a+b)/ab=2
a+b=2ab
-4a+5ab-4b/3a-2ab+3b=[-4(a+b)+5ab]/[3(a+b)-2ab]=(-8ab+5ab)/(6ab-2ab)=-3/4