y=sin(2x+π/6),x属于[π/6,3π/4],求值域

问题描述:

y=sin(2x+π/6),x属于[π/6,3π/4],求值域

π/6π/3π/2π/2sinx是减函数
所以sin(3π/2)-1而sin(2x+π/6)值域本身就是[-1,1]
所以3π/2所以值域[-1,1]