∫dx/(x-2)平方(x-3)
问题描述：
∫dx/(x-2)平方(x-3)
答
∫{1/[(x-2)^2(x-3)] } dx1/[(x-2)^2(x-3)] = A/(x-2) +B/(x-2)^2 + C/(x-3)=> 1 = A(x-2)(x-3) +B(x-3) +C(x-2)^2coef.of x^2A+C =0 (1)put x=2B=-1coef.of constant 1= 6A-3B +4C3A+2C = -1 (2)(2)-2(1)A = -1C= 1...