f(x)=3x^5-17x^4+12x^3+6x^2+9x+8,求f(-1/3)
问题描述：
f(x)=3x^5-17x^4+12x^3+6x^2+9x+8,求f(-1/3)
答
把x=-1/3直接代入f(x),就可以解出来.f(-1/3）=3x(-1/3)^5-17x(-1/3)^4+12x(-1/3)^3+6x(-1/3)^2+9x(-1/3)+8=-1/81-17/81+12x(-1/27)+6x1/9+9x(-1/3)+8=-18/81-4/9+6/9-3+8=-2/9-4/9+6/9+5=5