logx(x+1)+logx(x+2)=logx6+1
问题描述：
logx(x+1)+logx(x+2)=logx6+1
答
logx(x+1)+logx(x+2)=logx6+1logx(x+1)+logx(x+2)=logx(6)+logx(x)logx (x+1)(x+2)=logx (6x)(x+1)(x+2)=6xx²+3x+2=6xx²-3x+2=0(x-1)(x-2)=0x=1或x=2检验 x=1,底数为1,不满足,是增根所以 x=2...