（log4 3+log8 3）·（log3 2+log9 2）—log1/2×4次√32 +5^log25 9 化简
问题描述：
（log4 3+log8 3）·（log3 2+log9 2）—log1/2×4次√32 +5^log25 9 化简
答
分开三段来算：(log3 2+log9 2)*(log4 3+log8 3) =(lg2/lg3+lg2/lg9)*(lg3/lg4+lg3/lg8) =(lg2/lg3+lg2/2lg3)*(lg3/2lg2+lg3/3lg2 =3/2*lg2/lg3*5/6*lg3/lg2 =3/2*5/6=5/4 log1/2×4次√32 =log1/2 32的平方=-5 5^log25 9 =9 所以原式=5/4+5+9=15.25 是这样吗?