(1/a+1)+(2/a^2+1)+(4/a^4+1)+(8/a^8+1)+(16/a^16+1)-(32/a^32+1)
问题描述:
(1/a+1)+(2/a^2+1)+(4/a^4+1)+(8/a^8+1)+(16/a^16+1)-(32/a^32+1)
答
这个题上的 +1 应该是加到分母上吧 也就是这样 1/(a+1)+2/(a^2+1)+4/(a^4+1)+8/(a^8+1)+16/(a^16+1)-32/(a^32+1) = 1/(a-1)+[ -1/(a-1)+1/(a+1 ) ]+2/(a^2+1)+4/(a^4+1)+8/(a^8+1)+16/(a^16+1)-32/(a^...