如图所示电路,t
问题描述：
如图所示电路,t
答
tt≥0时,
i1=Cdu(t)/dt
i2=[3Cdu(t)/dt+u(t)]/6
i={25-[3Cdu(t)/dt+u(t)]}/(2+4)=i1+i2=Cdu(t)/dt+[3Cdu(t)/dt+u(t)]/6
即25/6-1/2Cdu(t)/dt-u(t)/6=3/2Cdu(t)/dt+u(t)/6
12Cdu(t)/dt+2u(t)=25
u(0)=15
示意图自己画吧