已知y=x2-3xy-2y2/2y,那么y/x=

问题描述:

已知y=x2-3xy-2y2/2y,那么y/x=

y=(x^2-3xy-2y^2)/2y
x^2-3xy-4y^2=0
(x-4y)(x+y)=0
x=4y或x=-y
x/y=4或-1