tan19°+tan41°+3tan19°tan41°的值为(  ) A.3 B.1 C.33 D.-3

问题描述:

tan19°+tan41°+

3
tan19°tan41°的值为(  )
A.
3

B. 1
C.
3
3

D. -
3

由两角和的正切公式可得tan(19°+41°)=tan19°+tan41°1−tan19°tan41°,∴tan19°+tan41°=tan(19°+41°)(1-tan19°tan41°)=tan60°(1-tan19°tan41°)=3(1-tan19°tan41°),∴tan19°+tan41°+3ta...