x方-6xy+9y方=0,求x-3/y-1的值(因式分解)
问题描述:
x方-6xy+9y方=0,求x-3/y-1的值(因式分解)
答
x²-6xy+9y²=0
(x-3y)²=0
x-3y=0
x=3y
(x-3)/(y-1)=(3y-3)/(y-1)=3