已知x2+y2-2x-6y+10=0,则4/(y+1/x)=
问题描述：
已知x2+y2-2x-6y+10=0,则4/(y+1/x)=
答
x^2+y^2-2x-6y+10=0x^2-2x+4+y^2-6y+6=0(x-2)^2+(y-3)^2=0x-2=0x=2y-3=0y=34/[y+(1/x)]=4/[3+(1/2)]=4/(7/2)=8/7 4/[(y+1)/x]=4/(3+1)/2=4/2=2==========后面你写的不明确