用因式分解法解方程:x^2+(1+2√2)x+√2(1+√2)=0

问题描述:

用因式分解法解方程:x^2+(1+2√2)x+√2(1+√2)=0

x^2+(1+2√2)x+√2(1+√2)=0
(x+√2)(x+1+√2)=0
x=-√2 或 -1-√2