X2+y2+2x-6y+10=0 则x-y=

问题描述:

X2+y2+2x-6y+10=0 则x-y=

x^2+y^2+2x-6y+10=x^2+2x+1+y^2-6x+9=(x+1)^2+(y-3)^2=0
因为:(x+1)^2>=0 (y-3)^2=0
所以:x=-1 y=3
x-y=-1-3=-4.